document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1170489>Question 1170489</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The number of accidents on a particular highway averages 4.4 per year. Assume that the number of accidents follows a Poisson distribution.\r<BR>\n" );
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document.write( "What is the probability that there are more than three accidents next year? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #795550 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=795550\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> probability of 0 1 2 3<BR>\n" );
document.write( "for 0 e^(-4.4)<BR>\n" );
document.write( "for 1, it is e^(-4.4)*4.4^1/1! <BR>\n" );
document.write( "for 2  it is e^(-4.4)*4.4^2/2!<BR>\n" );
document.write( "for 3 it is e^(-4.4)*4.4^3/6<BR>\n" );
document.write( "These are 0.0123+0.0540+0.1188+0.1743=0.3594<BR>\n" );
document.write( "the answer is the complement of that or 0.6406<BR>\n" );
document.write( "also calculator 1-poissoncdf(4.4,3)ENTER=0.6406<BR>\n" );
document.write( "the 1- is needed, because the calculator calculates left tail probability, and here we want the right tail. </SPAN>\n" );
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