document.write( "Question 1170661: Ken is 64 years younger than Julia. 9 years ago, Julia's age was 3 times Ken's age. How old is Ken now? \n" ); document.write( "
Algebra.Com's Answer #795540 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Here is a completely different way to solve this kind of problem....

\n" ); document.write( "Start with the fact that 9 years ago Julia's age was 3 times Ken's age. We can then say that their ages 9 years ago were 3x and x.

\n" ); document.write( "The difference between their ages 9 years ago is then 3x-x=2x. But we know the difference between their ages is (and always was/will be) 64.

\n" ); document.write( "So 2x=64; x=32; and their ages 9 years ago were 3x=96 and x=32.

\n" ); document.write( "Since that was 9 years ago, Ken's age is now 32+9=41.

\n" ); document.write( "ANSWER: Ken is 41

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