document.write( "Question 1170662: The length of a rectangular garden is two feet less than three times the width. If the area is 65ft², find the dimension.
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Algebra.Com's Answer #795536 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "if the length \"L\" of a rectangular garden is two feet less than three times the width \"W\" , we have\r
\n" ); document.write( "\n" ); document.write( "\"L=3W-2\" ....eq.1\r
\n" ); document.write( "\n" ); document.write( "if the area is \"65ft%5E2%2C+we+have%0D%0A%0D%0A%7B%7B%7BL%2AW=65\"....eq.2\r
\n" ); document.write( "\n" ); document.write( "substitute \"L\" from eq.1\r
\n" ); document.write( "\n" ); document.write( "\"%283W-2%29%2AW=65\"....solve for \"W\"\r
\n" ); document.write( "\n" ); document.write( "\"3W%5E2-2W=65\"\r
\n" ); document.write( "\n" ); document.write( "\"3W%5E2-2W-65=0\"....factor\r
\n" ); document.write( "\n" ); document.write( "\"3W%5E2%2B13W-15W-65=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%283W%5E2-15W%29%2B%2813W-65%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"3W%28W-5%29%2B13%28W-5%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28W+-+5%29+%283W+%2B+13%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "use only positive solution\r
\n" ); document.write( "\n" ); document.write( "->\"%28W+-+5%29+=+0\"=>\"W=5\"\r
\n" ); document.write( "\n" ); document.write( "go to eq.1 \r
\n" ); document.write( "\n" ); document.write( "\"L=3W-2\" ....eq.1, substitute \"W\"\r
\n" ); document.write( "\n" ); document.write( "\"L=3%2A5-2\" \r
\n" ); document.write( "\n" ); document.write( "\"L=13\" \r
\n" ); document.write( "\n" ); document.write( " dimension:\r
\n" ); document.write( "\n" ); document.write( "the length of a rectangular garden is \"13ft\" \r
\n" ); document.write( "\n" ); document.write( "the width of a rectangular garden is \"5ft\" \r
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