document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1170659>Question 1170659</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Wade is 70 years younger than Alma. 4 years ago, Alma's age was 3 times Wade's age. How old is Wade now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #795531 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=795531\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a way to solve the problem that is much different than the usual algebraic method shown by the other tutors.  Both solution methods are fine; I personally prefer this method because it gets me to the answer faster, using easier calculations.<br><BR>\n" );
document.write( "When Alma's age was 3 times Wade's age, their ages could be represented with x and 3x; making the difference between their ages 2x.<br><BR>\n" );
document.write( "The difference between their ages is (and always will be) 70 years; so 2x=70 and x=35.<br><BR>\n" );
document.write( "So their ages when Alma was 3 times as old as Wade were 3x=105 and x=35.<br><BR>\n" );
document.write( "That was 4 years ago, so their ages now are 105+4=109 and 35+4=39.<br><BR>\n" );
document.write( "ANSWER: Wade is now 39.<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );