document.write( "Question 1170640: How many 4 - digit even numbers can be formed from
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document.write( "the digits 0 to 9 if each digit is to be used only once in
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document.write( "each number ?
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Algebra.Com's Answer #795513 by ikleyn(52803)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "How many 4-digit even numbers can be formed from the digits 0 to 9 \n" ); document.write( "if each digit is to be used only once in each number ? \n" ); document.write( "~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "The fact that the number is an EVEN number means that the last digit is one of 5 even digits 0, 2, 4, 6, or 8.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "In my solution, I will consider two cases separately:\r\n" ); document.write( "\r\n" ); document.write( " case (a): the last digit is 0 (zero),\r\n" ); document.write( "\r\n" ); document.write( " and\r\n" ); document.write( "\r\n" ); document.write( " case (b): the last digit is any of the remaining 4 even digits 2, 4, 6 or 8.\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Case (a): the last digit is 0 (zero)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " Then the first (most-left) digit is any of 9 remaining digits;\r\n" ); document.write( "\r\n" ); document.write( " the second digit is any of remaining 8 digits;\r\n" ); document.write( "\r\n" ); document.write( " the third digit is any of remaining 7 digits.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " So, the total number of possible options is 9*8*7 = 504 in this case.\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Case (b): the last digit is any of remaining 4 digits 2, 4, 6 or 8.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " Then the first (most-left) digit is any of 8 remaining digits (keep in mind that the leading digit CAN NOT be 0 (!));\r\n" ); document.write( "\r\n" ); document.write( " the second digit is any of 8 remaining digits (zero is ALLOWED in this position);\r\n" ); document.write( "\r\n" ); document.write( " the third digit is any of 7 remaining digits (zero is ALLOWED in this position).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " So, the total number of possible options is 8*8*7 = 448 in this case.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Thus the total number of possibilities is 504 + 448 = 952.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ANSWER. 952 four-digit even numbers can be formed from the digits 0 to 9 if each digit is to be used only once in each number. \n" ); document.write( " \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The major lesson to learn from my solution is splitting the analysis in two cases.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |