document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1170460>Question 1170460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Triad’s	Car Rental charges $65/day, plus $0.20/km for a luxury car while Karr’s Car Rental charges $30/day,plus	$0.55/km for a luxury car. When is the cost to rent a luxury car the same? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #795489 by </B><A HREF=/tutors/aboutme.mpl?userid=akumpo><B>akumpo(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=akumpo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=akumpo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=795489\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using system of equations, where x is the number of km and y is the cost<BR>\n" );
document.write( "65+0.2x=y<BR>\n" );
document.write( "30+0.55x=y\r<BR>\n" );
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document.write( "Move the x variable to the other side to get:<BR>\n" );
document.write( "y-0.2x=65<BR>\n" );
document.write( "y-0.55x=30\r<BR>\n" );
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document.write( "Subtract the two equations to get rid of the y variable to get:<BR>\n" );
document.write( "0.35x=35<BR>\n" );
document.write( "Divide both side by 0.35 to get x=100\r<BR>\n" );
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document.write( "Plugging x into our equations, 65+0.2*100=65+20=85, 30+0.55*100=30+55=85\r<BR>\n" );
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document.write( "So the cost of renting a luxury at the same price for both companies is when you travel for 100km, or when the price is $85.<BR>\n" );
document.write( " </SPAN>\n" );
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