document.write( "Question 1170602: A speedboat travels at a rate of 20 kph in still water. It travels 55 km upstream in the same time
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document.write( "that it travels 90 km downstream. What is the rate of the current? \n" );
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Algebra.Com's Answer #795456 by josgarithmetic(39621)![]() ![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( " SPEED TIME DISTANCE\r\n" ); document.write( "UPSTREAM 20-c 55/(20-c) 55\r\n" ); document.write( "DOWNSTRE 20+c 90/(20+c) 90\r\n" ); document.write( " \n" ); document.write( "The two times are described as being equal. \n" ); document.write( " |