document.write( "Question 1170602: A speedboat travels at a rate of 20 kph in still water. It travels 55 km upstream in the same time
\n" ); document.write( "that it travels 90 km downstream. What is the rate of the current?
\n" ); document.write( "

Algebra.Com's Answer #795456 by josgarithmetic(39621)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "                  SPEED       TIME            DISTANCE\r\n" );
document.write( "UPSTREAM          20-c        55/(20-c)          55\r\n" );
document.write( "DOWNSTRE          20+c        90/(20+c)          90\r\n" );
document.write( "

\n" ); document.write( "The two times are described as being equal.
\n" ); document.write( "\"55%2F%2820-c%29=90%2F%2820%2Bc%29\"-----simplify and solve.
\n" ); document.write( "
\n" );