document.write( "Question 1170608: With a sample size of 900, the standard error is 3. What should be the sample size so that we could be 95% confident that the population mean is within 4 of the sample mean?
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document.write( "Answer=1945 \n" );
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Algebra.Com's Answer #795452 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the standard error is equal to the standard deviation divided by the square root of the sample size.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "with a sample size of 900, the standard error is 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this gets you the formula se = sd / sqrt(ss). \n" ); document.write( "se = standard error \n" ); document.write( "sd = standard deviation \n" ); document.write( "ss = sample size.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in your problem, the formula becomes 3 = sd / sqrt(900) \n" ); document.write( "solve for sd to get: \n" ); document.write( "sd = 3 * sqrt(900) = 3 * 30 = 90.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at 95% confidence level, the two tailed alpha will be .05/2 = .025.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the critical z-score becomes plus or minus 1.96\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the z-score formula becomes plur or minus 1.96 = (x - m) / se\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since se = sd / sqrt(ss), and since sd = 90, the formula becomes se = 90 / sqrt(ss).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula becomes plus or minus 1.96 = (x - m) / (90 / sqrt(ss)).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since you want the margin of error to be plus minus 4, then (x - m) must be equal to plus or minus 4, and the formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "plus or minus 1.96 = (plus or minus 4) / (90 / sqrt(ss))\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this is the same as:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "plus or minus 1.96 = (plus or minus 4) * sqrt(ss) / 90\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for sqrt(ss) to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sqrt(ss) = 90 * (plus or minus 1.96) / (plus or minus 4)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "just working on the plus sides of this equation, you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sqrt(ss) = 90 * 1.96 / 4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that gets you sqrt(ss) = 44.1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for ss to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ss = 1944.81.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's the answer your are looking for.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the other options will lead to the following results.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sqrt(ss) = 90 * -1.96 / -4 = 44.1, giving you the same answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sqrt(ss) = 90 * 1.96 / -4 = -44.1 which is not possible because it winds up being the square root of a negative number which is not real.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sqrt(ss) = 90 * -1.96 / 4 = -44.1 which is not real for the same reason.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the only real answer is 1944.81.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your solution is that the sample size is 1944.81.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to confirm, replace ss with 1944.81 in the problem to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "plus or minus 1.96 = (x - m) / (90/sqrt(1944.81).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for (x - m) to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x - m) = 1.96 * 90 / sqrt(1944.81) = 4 when 1.96 is positive.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x - m) = -1.96 * 90 / sqrt(1944.81) = -4 when 1.96 is negative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your margin of error is plus or minus 4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this works with any mean as long as the standard error is equal to 90 / sqrt(1944.81) = 2.040800586.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for example, if the mean is 7500, then you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = (7504 - 7500) / 2.040800586 = 1.96\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = (7496 - 7500) / 2.040800586 = -1.96\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the confidence interval is from 7496 to 7504.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the margin of error is plus or minus 4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "normally, you would round the answer to the next highest integer which would make it equal to a sample size of 1945.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that makes your margin of error slightly less than 4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for example:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1.96 = (x - m) / (90/sqrt(1945)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for (x - m) to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x - m) = 3.999804622.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's slightly less than 4, but if you round it to the 3 decimal places, it will be equal to 4.\r \n" ); 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