document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1170563>Question 1170563</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Kiran reaches into her pocket and finds 28 coins with a total value of $4.10. The coins are nickels, dimes or quarters only. There are twice as many quarters as dimes. How many of each type of coin does Kiran have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #795435 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13216)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=795435\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Certainly, if a formal algebraic solution is required, taking the time to analyze the problem to set up the problem using a single variable is much better than using several variables.<br><BR>\n" );
document.write( "But if a formal algebraic solution is not required, an informal solution using logical analysis and simple arithmetic can get you to the answer faster; and it can give you some very good brain exercise (i.e., valuable problem solving experience).<br><BR>\n" );
document.write( "(1) Because the number of quarters is twice the number of dimes, we can group the quarters and dimes into groups each containing two quarters and one dime.<BR>\n" );
document.write( "(2) The value of each such group is 60 cents; that means the total value of the quarters and dimes is a multiple of 60 cents.<BR>\n" );
document.write( "(3) The largest multiple of 60 cents that is less than the total of $4.10 (410 cents) is 6 times 60 cents, or 360 cents, or $3.60.  That leaves 50 cents to be made using the nickels.<br><BR>\n" );
document.write( "Check that answer.  The 6 groups of quarters and dimes contain a total of 6*3=18 coins; the 50 cents in nickels contains 50/5 = 10 coins.  18+10 = 28; the number of coins is right, so the solution is correct.<br><BR>\n" );
document.write( "ANSWER: 6 dimes and 12 quarters; and 10 nickels.<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );