document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1170567>Question 1170567</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In​ 2012, the population of a city was 5.82 million. The exponential growth rate was 2.95​% per year.<BR>\n" );
document.write( "​a) Find the exponential growth function.<BR>\n" );
document.write( "​b) Estimate the population of the city in 2018.<BR>\n" );
document.write( "​c) When will the population of the city be  ​million?<BR>\n" );
document.write( "​d) Find the doubling time. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #795425 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=795425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F(t)=5.82(1.0295)^t  where t= number of years after 2012<BR>\n" );
document.write( "F(6) or 2018=5.82^1.0285^6=6,888,882 or 6.89 million<BR>\n" );
document.write( "=<BR>\n" );
document.write( "1.0295)^t=2<BR>\n" );
document.write( "t ln (1.0295)=ln 2<BR>\n" );
document.write( "t=23.84 years doubling time<BR>\n" );
document.write( "=<BR>\n" );
document.write( "c is not clear. For 10 million, 10/5.82=1.718<BR>\n" );
document.write( "without rounding<BR>\n" );
document.write( "1.718=1.0295^t<BR>\n" );
document.write( "t=18.62 years<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );