document.write( "Question 1170565: One number is seven less than a second number. Six times the first is 6 more than 4 times the second. Find the numbers \n" ); document.write( "

Algebra.Com's Answer #795416 by ikleyn(52803) $\"\"$ $\"About$

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document.write( "Let x be \"the second number\";\r\n" );
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document.write( "then the first number is  x-7, according to the condition.\r\n" );
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document.write( "Based on the second condition, you can write this equation\r\n" );
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document.write( "    6*(x-7) = 4*x + 6.\r\n" );
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document.write( "Simplify it and get the answer\r\n" );
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document.write( "    6x - 42 = 4x + 6\r\n" );
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document.write( "    6x - 4x = 6 + 42\r\n" );
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document.write( "      2x    = 48\r\n" );
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document.write( "       x    = 48/2 = 24.\r\n" );
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document.write( "ANSWER.  Second number is 24;  first number is seven less, i.i. 23-7 = 17.\r\n" );
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document.write( "CHECK.   Six times the first is 6*17 = 102;  4 times the second is 4*24 = 96.  The difference is 4.   ! Correct !\r\n" );
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