document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1170472>Question 1170472</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the hyperbola with center at the origin, foci at (-4,0) and (4,0), and eccentricity of 5/4. </SPAN>\n" );
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document.write( "Foci at (-4,0) and (4,0) means the equation is of the general form<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2Fa%5E2-y%5E2%2Fb%5E2+=+1 ALIGN=MIDDLE  ALT=\"x%5E2%2Fa%5E2-y%5E2%2Fb%5E2+=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "a is the distance from the center to each end of the transverse axis (i.e., to each vertex); b is the distance from the center to each end of the conjugate axis (i.e. to each co-vertex).  a and b are related by<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%5E2+=+a%5E2%2Bb%5E2 ALIGN=MIDDLE  ALT=\"c%5E2+=+a%5E2%2Bb%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "where c is the distance from the center to each focus.<br><BR>\n" );
document.write( "The eccentricity is c/a.<br><BR>\n" );
document.write( "The given information is c=4 and eccentricity = 5/4.<br><BR>\n" );
document.write( "(1) Use c and the eccentricity to find a.<br><BR>\n" );
document.write( "(2) Use <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%5E2+=+a%5E2%2Bb%5E2 ALIGN=MIDDLE  ALT=\"c%5E2+=+a%5E2%2Bb%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > to find b.<br><BR>\n" );
document.write( "(3) Plug the a^2 and b^2 values into the general form of the equation.<br><BR>\n" );
document.write( " </SPAN>\n" );
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