document.write( "Question 1170449: Solve the equation sin^2x = 3cos^2x.\r
\n" ); document.write( "\n" ); document.write( "The value of x that satisfies the equation if x lies in the second quadrant is
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\n" ); document.write( "\n" ); document.write( "a. 60°
\n" ); document.write( "b. 120°
\n" ); document.write( "c. 150°
\n" ); document.write( "d. 240°
\n" ); document.write( "e. 300°
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Algebra.Com's Answer #795324 by Alan3354(69443)\"\" \"About 
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Solve the equation sin^2(x) = 3cos^2(x)
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\n" ); document.write( "Use parentheses.
\n" ); document.write( "sin^2(x) = 3cos^2(x)
\n" ); document.write( "1 - cos^2(x) = 3cos^2(x)
\n" ); document.write( "4cos^2(x) = 1
\n" ); document.write( "cos^2(x) = 1/4
\n" ); document.write( "cos(x) = -1/2, +1/2
\n" ); document.write( "etc
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\n" ); document.write( "Another method
\n" ); document.write( "sin^2(x)/cos^2(x) = 3
\n" ); document.write( "tan^2(x) = 3
\n" ); document.write( "tan(x) = -sqrt(3), +sqrt(3)
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