document.write( "Question 1170449: Solve the equation sin^2x = 3cos^2x.\r
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document.write( "The value of x that satisfies the equation if x lies in the second quadrant is
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document.write( "a. 60°
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document.write( "b. 120°
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document.write( "c. 150°
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document.write( "d. 240°
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document.write( "e. 300° \n" );
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Algebra.Com's Answer #795324 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Solve the equation sin^2(x) = 3cos^2(x) \n" ); document.write( "--- \n" ); document.write( "Use parentheses. \n" ); document.write( "sin^2(x) = 3cos^2(x) \n" ); document.write( "1 - cos^2(x) = 3cos^2(x) \n" ); document.write( "4cos^2(x) = 1 \n" ); document.write( "cos^2(x) = 1/4 \n" ); document.write( "cos(x) = -1/2, +1/2 \n" ); document.write( "etc \n" ); document.write( "=================== \n" ); document.write( "Another method \n" ); document.write( "sin^2(x)/cos^2(x) = 3 \n" ); document.write( "tan^2(x) = 3 \n" ); document.write( "tan(x) = -sqrt(3), +sqrt(3) \n" ); document.write( " \n" ); document.write( " |