document.write( "Question 1170439: Find an equation for the parabola that has its vertex at the origin and satisfies the given condition.
\n" ); document.write( "Directrix y = 1/6\r
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Algebra.Com's Answer #795311 by MathLover1(20849)\"\" \"About 
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given:
\n" ); document.write( "the parabola that has its vertex at the origin => (\"h\",\"k\")=(\"0\",\"0\")
\n" ); document.write( "and that directrix \"y+=+1%2F6\"\r
\n" ); document.write( "\n" ); document.write( "The standard form is \"%28x+-+h%29%5E2+=+4p+%28y+-+k%29\", where the focus is (\"h\", \"k+%2B+p\") and the directrix is \"y+=+k+-+p\". If the parabola is rotated so that its vertex is (\"h\",\"k\") and its axis of symmetry is parallel to the \"x\"-axis, it has an equation of \"%28y+-+k%29%5E2+=+4p+%28x+-+h%29\", where the focus is (\"h+%2B+p\", \"k\") and the directrix is \"x+=+h+-+p\"}\r
\n" ); document.write( "\n" ); document.write( "so. use \"%28x+-+h%29%5E2+=+4p+%28y+-+k%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+0%29%5E2+=+4p+%28y+-+0%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+4p+%2Ay+\"\r
\n" ); document.write( "\n" ); document.write( "\"y=x%5E2+%2F4p+\"\r
\n" ); document.write( "\n" ); document.write( "since directrix \"y+=+1%2F6\", the directrix is \"y+=+k+-+p\", and \"k=0\", we have\r
\n" ); document.write( "\n" ); document.write( "\"1%2F6+=+0+-+p\"\r
\n" ); document.write( "\n" ); document.write( "\"p+=++-+1%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=x%5E2+%2F%284%28-+1%2F6%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"y=x%5E2+%2F%28-4%2F6%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"y=x%5E2+%2F%28-2%2F3%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%28-3%2F2%29+x%5E2+\"-> your answer\r
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\n" ); document.write( "\n" ); document.write( "the focus is (\"h\", \"k+%2B+p\") =(\"0\", \"-+1%2F6\")\r
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