document.write( "Question 1170388: Which of the following is a solution to sin(2x)-cosx=0?\r
\n" ); document.write( "\n" ); document.write( "a. 60 degrees
\n" ); document.write( "b. 90 degrees
\n" ); document.write( "c. 120 degrees
\n" ); document.write( "d. 240 degrees
\n" ); document.write( "e. 300 degrees
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Algebra.Com's Answer #795277 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "\"sin%282x%29-cos%28x%29=0\"\r
\n" ); document.write( "\n" ); document.write( "rewrite using trig identities \"sin%282x%29=2sin%28x%29cos%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "\"2sin%28x%29cos%28x%29-cos%28x%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%282sin%28x%29+-1%29cos%28x%29=0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "\"2sin%28x%29+-1=0\" ->\"sin%28x%29=1%2F2\"
\n" ); document.write( "or
\n" ); document.write( "\"cos%28x%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "if \"sin%28x%29=1%2F2\" then \"sin%5E-1%281%2F2%29=30\"°
\n" ); document.write( "if \"cos%28x%29=0\" then \"cos%5E-1%280%29=90\"°\r
\n" ); document.write( "\n" ); document.write( "answer: b. \"90\" degrees\r
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