document.write( "Question 1170293: The length of the floor is 32m longer than its width and there is more than 200 square meters. You will cover the floor completely with tiles. What will be the possible dimensions of the floor? \n" ); document.write( "
Algebra.Com's Answer #795263 by Clanther(6)\"\" \"About 
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let x be the width
\n" ); document.write( "Equation:
\n" ); document.write( "(32+x)x>200
\n" ); document.write( "x²+32x>200\r
\n" ); document.write( "\n" ); document.write( "To find the roots:
\n" ); document.write( "x²+32x-200=0
\n" ); document.write( "by completing the square:
\n" ); document.write( "x²+32x+256=200+256
\n" ); document.write( "(x+16)²=±√456
\n" ); document.write( "x=-16±21.35
\n" ); document.write( "Use the positive value of the factors since we are looking for measurement.
\n" ); document.write( "x=-16+21.35
\n" ); document.write( "x=5.35m width
\n" ); document.write( "length
\n" ); document.write( "32+5.35=37.35m\r
\n" ); document.write( "\n" ); document.write( "The possible dimensions are:
\n" ); document.write( "6m by 38m, 7m by 39m, 8m by 40m and so on...\r
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