document.write( "Question 1169990: suppose that the lifetimes of light bulbs are approximately normally distributed, with a mean of 57 hours and a standard deviation 3.3 of hours. with this information, answer the following questions.
\n" );
document.write( "(a) what proportion of light bulbs will last more than 60 hours?
\n" );
document.write( "(b) what proportion of light bulbs will last 51 hours or less?
\n" );
document.write( "(c) what proportion of light bulbs will last between 57 and 61 hours?
\n" );
document.write( "(d) what is the probability that a randomly selected light bulb lasts less than 45 hours? \n" );
document.write( "
Algebra.Com's Answer #795252 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( "the first will be z > 3/3.3 or z > 0.909 . That probability is 0.1817 \n" ); document.write( "- \n" ); document.write( "the second will be z < -6/3.3 and that probability is 0.0345 \n" ); document.write( "- \n" ); document.write( "the third is 0.3873. Calculator 2ndVARS 2 normalcdf(57,61,57,3.3)ENTER \n" ); document.write( "- \n" ); document.write( "the last is z < -12/3.3 and probability is 0.0001 \n" ); document.write( " |