document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1170343>Question 1170343</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a right triangle is such that the shortest side is 7 inches shorter than the longest and the other side is only 1 inch shorter than the longest side.find the length of the 3 sides  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #795245 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=795245\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x is shortest side<BR>\n" );
document.write( "x+7 is longest<BR>\n" );
document.write( "x+6 is the third<BR>\n" );
document.write( "x^2+(x+6)^2=(x+7)^2<BR>\n" );
document.write( "x^2+x^2+12x+36=x^2+14x+49<BR>\n" );
document.write( "x^2-2x-13=0<BR>\n" );
document.write( "x=(1/2)(2+/- sqrt (4+52)<BR>\n" );
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document.write( "x=1+sqrt(14)<BR>\n" );
document.write( "x+6=7+sqrt(14)<BR>\n" );
document.write( "hypot=8+sqrt(14)\r<BR>\n" );
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document.write( "1+2 sqrt(14)+14<BR>\n" );
document.write( "49+14sqrt(14)+14=<BR>\n" );
document.write( "64+16 sqrt(14)+14, as it should be.<BR>\n" );
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document.write( "side lengths are 1+ sqrt(14), 7 +sqrt (14), and 8 +sqrt (14)\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );