document.write( "Question 109066: At GE shift 1 produced 4 times as much as shift 2. GE's total production for July was 5,500 Jet engines. What was the output for each shift?\r
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Algebra.Com's Answer #79524 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Shift 1 produced x number of engines. Shift 2 produced 4 times as many engines which means
\n" ); document.write( "that Shift 2 produced 4x engines. Together these shifts produced x + 4x engines and this
\n" ); document.write( "is to total 5500 engines for the month.
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\n" ); document.write( "So you can write the equation:
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\n" ); document.write( "x + 4x = 5500
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\n" ); document.write( "Add the two terms on the left side:
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\n" ); document.write( "5x = 5500
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\n" ); document.write( "Solve for x by dividing both sides by 5 to get:
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\n" ); document.write( "x = 5500/5 = 1100 engines
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\n" ); document.write( "So Shift 1 produced 1100 engines. Since Shift 2 produced 4 times as much then the output
\n" ); document.write( "by Shift 2 is 4 times 1100 or 4400 engines.
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\n" ); document.write( "This checks because 1100 engines + 4400 engines equals 5500 engines for July.
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\n" ); document.write( "Hope this helps you understand the problem.
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