document.write( "Question 1170337: Given the parabola having the equation x^2+4y+8x=4, find the vertex, focus, and the length of the latus rectum. Sketch the graph. \n" ); document.write( "
Algebra.Com's Answer #795237 by josgarithmetic(39616)\"\" \"About 
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\"x%5E2%2B8x=4-4y\"
\n" ); document.write( "\"x%5E2%2B8x%2B16=4-4y%2B16\"
\n" ); document.write( "\"%28x%2B4%29%5E2=-4y%2B20\"
\n" ); document.write( "\"highlight%28%28x%2B4%29%5E2=-4%28y%2B5%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "The equation now shows parabola is concave downward with vertex as maximum point.\r
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\n" ); document.write( "\n" ); document.write( "------------------
\n" ); document.write( "Vertex (-4,-5)
\n" ); document.write( "----------------------------------------------------------
\n" ); document.write( "Distance between vertex and either focus or directrix is 1.
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\n" ); document.write( "Focus (-4,-6)
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\n" ); document.write( "Directrix \"y=-4\"
\n" ); document.write( "---------------------------------------------------------\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28500%2C500%2C-10%2C4%2C-10%2C4%2C-%281%2F4%29%28x%2B4%29%5E2-5%29\"
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