document.write( "Question 1170327: A rectangle is 2 inches longer than it is wide. Numerically, its area exceeds its perimeter by 31. Find the perimeter.\r
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Algebra.Com's Answer #795209 by Clanther(6)\"\" \"About 
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let x be the width
\n" ); document.write( "let x+2 be the length
\n" ); document.write( "A=area
\n" ); document.write( "P=perimeter
\n" ); document.write( "A=lw
\n" ); document.write( " =x(x+2)
\n" ); document.write( "A=x²+2x\r
\n" ); document.write( "\n" ); document.write( "P=2x+2(x+2)
\n" ); document.write( " =2x+2x+4
\n" ); document.write( "P=4x+4
\n" ); document.write( "The equation is:
\n" ); document.write( " area-perimeter=31
\n" ); document.write( " (x²+2x)-(4x+4)=31
\n" ); document.write( " x²+2x-4x-4=31
\n" ); document.write( " x²-2x-4-31=0
\n" ); document.write( " x²-2x-35=0
\n" ); document.write( "by completing the square:
\n" ); document.write( " x²-2x+1=35+1
\n" ); document.write( " (x-1)²=36
\n" ); document.write( " √(x-1)²=±√36
\n" ); document.write( " x-1=±6
\n" ); document.write( "Take the positive value of the roots/factors
\n" ); document.write( " x=1+6
\n" ); document.write( " x=7 - the width
\n" ); document.write( "Substitute the value of x to the length representation:
\n" ); document.write( " x+2= 7+2= 9-the length
\n" ); document.write( "Perimeter: Substitute the positive value of the root(width) to:
\n" ); document.write( " P=4x+4
\n" ); document.write( " =4(7)+4
\n" ); document.write( " P=32\"
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