document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1170309>Question 1170309</A>: <I><SPAN STYLE=\"word-break: break-all;\"> substitution I NEED HELP D:\r<BR>\n" );
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document.write( "y=6x-11<BR>\n" );
document.write( "-2x-3y=-7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #795177 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=795177\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in the second equation of -2x-3y=-7<BR>\n" );
document.write( "multiply through by -1 to change all signs. 2x+3y=7 It is easier dealing with plus.<BR>\n" );
document.write( "substitute 6x-11 for y so 3y=3(6x-11) or 18x-33<BR>\n" );
document.write( "so 2x+18x-33=7<BR>\n" );
document.write( "20x=40<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "y-6x-11 or 1<BR>\n" );
document.write( "(2, 1)<BR>\n" );
document.write( " </SPAN>\n" );
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