document.write( "Question 1170262: find the three cube roots of 6-2i and express the roots in polar form. \n" ); document.write( "
Algebra.Com's Answer #795124 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! find the three cube roots of 6-2i and express the roots in polar form. \r \n" ); document.write( "\n" ); document.write( "First we plot the point 6-2i which is the point (6,-2), x=6, y=-2 \n" ); document.write( "We draw a vector from(0,0) to (6,-2).\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The hypotenuse is \n" ); document.write( "\n" ); document.write( "Calculate θ by \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So 6-2i in polar form is \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We can add any integer times 360° to the angle without changing the value:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We raise both side to the 1/3 power, the same as taking cube root, and write \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Next we use DeMoivre's theorem, which is to raise the modulus to the 1/3 \n" ); document.write( "power and multiply the argument by 1/3:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "[Write all three values out].\r \n" ); document.write( "\n" ); document.write( "Or if you want it in radians, substitute \n" ); document.write( "\n" ); document.write( "Edwin\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |