document.write( "Question 1170262: find the three cube roots of 6-2i and express the roots in polar form. \n" ); document.write( "
Algebra.Com's Answer #795124 by Edwin McCravy(20060)\"\" \"About 
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find the three cube roots of 6-2i and express the roots in polar form. \r
\n" ); document.write( "\n" ); document.write( "First we plot the point 6-2i which is the point (6,-2), x=6, y=-2
\n" ); document.write( "We draw a vector from(0,0) to (6,-2).\r
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\n" ); document.write( "\n" ); document.write( "The hypotenuse is , but we'll leave it \"sqrt%2840%29\" for now.\r
\n" ); document.write( "\n" ); document.write( "Calculate θ by \"tan%28reference%29=2%2F6=1%2F3%29\", so \"theta=tan%5E%28-1%29%281%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "So 6-2i in polar form is \r
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\n" ); document.write( "\n" ); document.write( "We can add any integer times 360° to the angle without changing the value:\r
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\n" ); document.write( "\n" ); document.write( "We raise both side to the 1/3 power, the same as taking cube root, and write
\n" ); document.write( "\"sqrt%2840%29\" as the 1/2 power of 40\r
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\n" ); document.write( "\n" ); document.write( "Next we use DeMoivre's theorem, which is to raise the modulus to the 1/3
\n" ); document.write( "power and multiply the argument by 1/3:\r
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\n" ); document.write( "\n" ); document.write( " where n=0,1,2\r
\n" ); document.write( "\n" ); document.write( "[Write all three values out].\r
\n" ); document.write( "\n" ); document.write( "Or if you want it in radians, substitute \"2pi%2F3\" for 120°\r
\n" ); document.write( "\n" ); document.write( "Edwin\r
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