document.write( "Question 1170208: A car rental company rents cars for $150 a day and vans for $300 a day. One day the total number of cars is 6 more than twice the number of vans and made $5700. How many cars and how many vans did the company sell on this day? \n" ); document.write( "
Algebra.Com's Answer #795109 by Theo(13342)\"\" \"About 
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c = number of cars
\n" ); document.write( "v = number of vans
\n" ); document.write( "cars cost 150 each and vans cost 300 each
\n" ); document.write( "total cost if 5700
\n" ); document.write( "equation is:
\n" ); document.write( "150c + 300v = 5700
\n" ); document.write( "you are given that the number of cars rented is 6 more than twice the number of vans rented.
\n" ); document.write( "the equation for that is:
\n" ); document.write( "c = 2v + 6
\n" ); document.write( "in the equation of 150c + 300v = 5700, replace c with 2v + 6 to get:
\n" ); document.write( "150 * (2v + 6) + 300v = 5700
\n" ); document.write( "simplify to get:
\n" ); document.write( "300v + 900 + 300v = 5700
\n" ); document.write( "subtract 900 from both sides of the equation and combine like terms to get:
\n" ); document.write( "600v = 4800
\n" ); document.write( "solve for v to get:
\n" ); document.write( "v = 8
\n" ); document.write( "replace v with 8 in the equation of 150c + 300v = 5700 and simplify to get:
\n" ); document.write( "150c + 2400 = 5700
\n" ); document.write( "subtract 2400 from both sides of the equation to get:
\n" ); document.write( "150c = 3300
\n" ); document.write( "solve for c to get:
\n" ); document.write( "c = 3300/150 = 22
\n" ); document.write( "you have 22 cars and 8 vans that are rented that day for a total of 5700.
\n" ); document.write( "22 * 150 + 8 * 300 = 3300 + 2400 = 5700
\n" ); document.write( "this confirms the number of cars and vans are good.
\n" ); document.write( "your solution is that they rented 22 cars and 8 vans that day.\r
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