document.write( "Question 1170149: The polynomial of degree 4, P ( x ) has a root of multiplicity 2 at x = 3 and roots of multiplicity 1 at x = 0 and x = − 2 . It goes through the point ( 5 , 56 ) . Find a formula for P ( x ) .\r
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document.write( "P(x)= \n" );
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Algebra.Com's Answer #795062 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! The equation for P(x) with the form P(x) = a*x(x-3)^2(x+2), will have roots \n" ); document.write( "at x=0, x=-2 and a double root at x=3. Now we need to find the parameter a \n" ); document.write( "from the point (5,56). \n" ); document.write( "P(5) = a(5)(2)^2(7) = 140a = 56 \n" ); document.write( "Thus a = 56/140 = 0.4 \n" ); document.write( "Ans: P(x) = 0.4x(x+2)(x-3)^2 \n" ); document.write( " |