document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1170197>Question 1170197</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a tour bus leaves sacramento every friday evening at 6:00 pm for a 270 mile trip to las vegas. due to mechanical problems the bus will be leaving at 6:30 pm today. to arrive in vegas at the same time, the driver must go 6 mph faster than usual. what is the buses normal speed ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #795055 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=795055\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> normal speed of bus is 270mi/x where x is number of hours<BR>\n" );
document.write( "speed of bus leaving at 6:30  and distance is 270 miles, so speed is 270/x-0.5.<BR>\n" );
document.write( "(270/x)+6=270/(x-0.5)<BR>\n" );
document.write( "(270+6x)/x=270/(x-0.5)<BR>\n" );
document.write( "270x=270x-135+6x^2-3x<BR>\n" );
document.write( "0=6x^2-3x-135<BR>\n" );
document.write( "0=(x-5)(6x+27)<BR>\n" );
document.write( "x=5 hours only positive root<BR>\n" );
document.write( "54 mph is normal speed (270/5)<BR>\n" );
document.write( "-<BR>\n" );
document.write( "when the bus goes 60 mph, it takes 4.5 hours, </SPAN>\n" );
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