document.write( "Question 1170177: A cruise ship going across a lake 15km wide travels a distance of 6km at a certain
\n" ); document.write( "speed and then finishes the trip at a speed 1 kph slower than its original speed. The
\n" ); document.write( "boat arrives 20 minutes later than if the original speed is maintained throughout the
\n" ); document.write( "trip. What is the original speed of the cruise ship?
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Algebra.Com's Answer #795038 by ankor@dixie-net.com(22740)\"\" \"About 
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A cruise ship going across a lake 15km wide travels a distance of 6km at a certain speed and then finishes the trip at a speed 1 kph slower than its original speed.
\n" ); document.write( " The boat arrives 20 minutes later than if the original speed is maintained throughout the trip.
\n" ); document.write( "What is the original speed of the cruise ship?
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\n" ); document.write( "let s = original speed
\n" ); document.write( "then
\n" ); document.write( "(s-1) = slower speed
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\n" ); document.write( "Change 20 min to \"1%2F3\" hr
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\n" ); document.write( "Total dist was 15 km therefore he traveled 6 km at s and 9 km at (s-1)
\n" ); document.write( "Find the actual time take for the trip
\n" ); document.write( "\"6%2Fs\" + \"9%2F%28%28s-1%29%29\" = \"%286%28s-1%29%2B9s%29%2F%28s%28s-1%29%29\" = \"%286s-6%2B9s%29%2F%28s%28s-1%29%29\" = \"%2815s-6%29%2F%28s%28s-1%29%29\"
\n" ); document.write( "then
\n" ); document.write( "actual time - normal time = 1/3 hr
\n" ); document.write( "\"%2815s-6%29%2F%28s%28s-1%29%29\" - \"15%2Fs\" = \"1%2F3\"
\n" ); document.write( "multiply by 3s(s-1), get rid of the denominators
\n" ); document.write( "3(15s-6) - 15(3(s-1)) = s(s-1)
\n" ); document.write( "45s - 18 - 45s + 45 = s^2 - s
\n" ); document.write( "27 = s^2 - s
\n" ); document.write( "A quadratic equation
\n" ); document.write( "s^2 - s - 27 = 0
\n" ); document.write( "using the quadratic formula, the positive solution
\n" ); document.write( "s = 5.72 km/h is the normal speed
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\n" ); document.write( "seems like we deserve to get an integer here, check in time equation with calc
\n" ); document.write( "(\"6%2F5.72\" + \"9%2F4.72\") - \"15%2F5.72\" =
\n" ); document.write( "1.049 + 1.907 - 2.622 = .334 which is about 1/3 hr or 20 min
\n" ); document.write( "seems to check out, if you find that I screwed this up, let me know. ankor@att.net
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