document.write( "Question 1921: The directions for this say to solve the equation by \"suitable methods\"....I am confused. Please help.
\n" ); document.write( "y-1=[(y+1)/4]^1/2
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Algebra.Com's Answer #795 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
first, square both sides... \"%28y-1%29%5E2\" = (y+1)/4 then move the 4 to the other side and multiply out the bracket...\r
\n" ); document.write( "\n" ); document.write( "\"4y%5E2+-+8y+%2B+4+=+y+%2B+1\"\r
\n" ); document.write( "\n" ); document.write( "now get everything on one side... \"4y%5E2+-+9y+%2B3+=+0\"\r
\n" ); document.write( "\n" ); document.write( "Solve this now, ie find the y value(s) where all this does equal zero.\r
\n" ); document.write( "\n" ); document.write( "Best way is factorising, but i don't think this factorises well, so that leaves the quadratic formula as the best solution.\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%28-b+%2B-+sqrt%28b%5E2+-+4ac%29%29%2F%282a%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%289+%2B-+sqrt%2881+-+4%2A4%2A3%29%29%2F%288%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%289+%2B-+sqrt%2833%29%29%2F8%29\"\r
\n" ); document.write( "\n" ); document.write( "so \"y+=+%289%2Bsqrt%2833%29%29%2F8%29\" or \"y+=+%289-sqrt%2833%29%29%2F8%29\"\r
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\n" ); document.write( "\n" ); document.write( "jon.
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