document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1170104>Question 1170104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Vertex form of y = 4x^2+12x+8. Please show your solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #794998 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=794998\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Vertex form is y = a(x-h)^2 + k, where (h,k) is the vertex<BR>\n" );
document.write( "The x-coordinate of the vertex, h = -b/2a = -12/8 = -3/2<BR>\n" );
document.write( "Thus, k = 4(-3/2)^2 + 12(-3/2) + 8 = 4(9/4) - 10 = -1<BR>\n" );
document.write( "So we have y = 4(x+3/2)^2 - 1 </SPAN>\n" );
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