document.write( "Question 1170066: Raymond, Joe, and Mike are brothers. Raymond is the oldest and Mike is the youngest. The sum of the ages of the 3 brothers is 24. The difference between Joe and Mike’s age is 2 years. Raymond’s age is 2 more than three times Josh’s age.\r
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\n" ); document.write( "\n" ); document.write( "Find the age of each brother.\r
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Algebra.Com's Answer #794931 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"m%3Cj%3Cr\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28m%2Bj%2Br=24%2Cj-m=2%2Cr=3j%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Last two equations are same as \"system%28m=j-2%2Cand%2Cr=3j%2B2%29\".\r
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\n" ); document.write( "\n" ); document.write( "The age-sum equation can be written, \"%28j-2%29%2Bj%2B%283j%2B2%29=24\".
\n" ); document.write( "(something is not right here. Check for any mistake in this work.)
\n" ); document.write( "(\"Josh\", or \"Joe\"?)
\n" ); document.write( "Assuming \"Joe\", no \"Josh\".
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\n" ); document.write( "\"j-2%2Bj%2B3j%2B2=24\"
\n" ); document.write( "\"5j=24\"
\n" ); document.write( "\"highlight%28j=24%2F5=4%264%2F5%29\"-------Joe
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