document.write( "Question 1170013: fourteen articles are bought. Some cost $2.00 each and the remainder cost $2.25 each.If the total amount spend is $30, how many of each article are bought \n" ); document.write( "
Algebra.Com's Answer #794884 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "(1) Using formal algebra....

\n" ); document.write( "x = # articles at $2 each
\n" ); document.write( "(14-x) = # articles at $2.25 each

\n" ); document.write( "\"x%282.00%29%2B%2814-x%29%282.25%29+=+30.00\"

\n" ); document.write( "Solve using basic algebra.

\n" ); document.write( "You should certainly know how to set up and solve the problem like that, or in another similar way, using formal algebra.

\n" ); document.write( "If a formal algebraic solution is not required (for example, in a timed math competition where getting an answer as fast as possible is desired), there are many other ways to solve the problem.

\n" ); document.write( "(2) Informally, using logical reasoning and some simple arithmetic....

\n" ); document.write( "All 14 articles at $2.00 each would be $28.00, which is $2.00 short of the actual total.
\n" ); document.write( "Each of the articles selling for $2.25 costs $0.25 more than one selling for $2.00.
\n" ); document.write( "The number of articles selling at $2.25 each, in order to make up the additional $2.00, is $2.00 divided by $0.25, which is 8.

\n" ); document.write( "ANSWER: 8 articles at $2.25 each and 14-8=6 articles at $2.00 each.

\n" ); document.write( "CHECK: 8(2.25) + 6(2.00 = 18+12 = 30

\n" ); document.write( "(3) And yet another solution using logical reasoning....

\n" ); document.write( "The total cost is an even whole dollar amount; and the total cost of any number of $2.00 items will be an even whole dollar amount.
\n" ); document.write( "So the total cost of the items at $2.25 each must be an even whole dollar amount.
\n" ); document.write( "The only number of items (less than 14) at $2.25 each for which the total is an even whole number of dollars is 8: 8($2.25) = $18.

\n" ); document.write( "So there must be 8 items at $2.25 each and 14-8=6 items at $2 each.

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