document.write( "Question 1169998: The problem I got incorrect:
\n" );
document.write( "Find inverse of h(x)=(3/4)x+12
\n" );
document.write( "My steps...
\n" );
document.write( "1) y = (3/4)x+12
\n" );
document.write( "2) (4/3)y = x+12
\n" );
document.write( "3) (4/3)y-12 = x
\n" );
document.write( "4) (4/3)x-12 = y
\n" );
document.write( "5) h^-1(x) = (4/3)x-12\r
\n" );
document.write( "\n" );
document.write( "Am told correct answer should be h^-1(x) = (4/3)(x-12).
\n" );
document.write( "Could someone explain the property I missed applying?
\n" );
document.write( "Thank you. \n" );
document.write( "
Algebra.Com's Answer #794860 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( "this method is crude: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The inverse of h is |