document.write( "Question 109006: Please help\r
\n" ); document.write( "\n" ); document.write( "8x^3 - 6x^2 + 2x / 4x+1= 8*x^3-6*x^2+3/2. Is this correct?
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Algebra.Com's Answer #79475 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"%288x%5E3+-+6x%5E2+%2B+2x%29+%2F+%284x%2B1%29\"………factor out \"x\" in nominator \r
\n" ); document.write( "\n" ); document.write( "\"x%288x%5E2+-+6x+%2B+2%29+%2F+%284x%2B1%29\"………write \"6x\" as \"2x\" – \"8x\"\r
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\n" ); document.write( "\n" ); document.write( "x(8x^2 + 2x – 8x + 2)/(4x + 1)….…..group \"8x%5E2+%2B+2x\" and –\"+8x+%2B+2\"\r
\n" ); document.write( "\n" ); document.write( "x((8x^2 + 4x) – (8x + 2))/(4x + 1) here \"8x%5E2+%2B+2x\" factor out \"2x\", and here -\"%288x+%2B+2%29\" factor out \"2\"\r
\n" ); document.write( "\n" ); document.write( "Then we have:\r
\n" ); document.write( "\n" ); document.write( "x(2x(4x + 1) – 2(4x + 1))/(4x + 1)..factor out \"4x%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"x%28%284x+%2B+1%29%282x+-+2%29%29%2F%284x+%2B+1%29\"…..cancel \"4x%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"x%282x+-+2%29%29\"…..factour out \"2\"\r
\n" ); document.write( "\n" ); document.write( "\"2x%28x+-+1%29\"\r
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