document.write( "Question 1169858: A food manufacturer produces regular and lite smoked sausages. A regular
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Algebra.Com's Answer #794736 by AnlytcPhil(1806)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Let x = the number of pounds of regular sausage produced\r\n" );
document.write( "0.72x = the number of pounds of pork used to make the x pounds of regular sausage\r\n" );
document.write( "0.28x = the number of pounds of turkey used to make the x pounds of regular sausage\r\n" );
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document.write( "Let y = the number of pounds of lite sausage produced\r\n" );
document.write( "0.22y = the number of pounds of pork used to make the y pounds of lite sausage\r\n" );
document.write( "0.78y = the number of pounds of turkey used to make the y pounds of lite sausage\r\n" );
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document.write( "\"system%280.72x+%2B+0.22y+=+2000%2C0.28x+%2B+0.78y+=+2000%29\"\r\n" );
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document.write( "Multiply both equations by 100\r\n" );
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document.write( "\"system%2872x+%2B+22y+=+200000%2C28x+%2B+78y+=+200000%29\"\r\n" );
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document.write( "Divide both equations by 2\r\n" );
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document.write( "\"system%2836x+%2B+11y+=+100000%2C14x+%2B+39y+=+100000%29\"\r\n" );
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document.write( "To eliminate x, multiply the first equation by 14 and\r\n" );
document.write( "the second by -36\r\n" );
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document.write( "\"system%28504x+%2B+154y+=+1400000%2C-504x+-+1404y+=+-3600000%29\"\r\n" );
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document.write( "Add them term by term\r\n" );
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document.write( "\"-1250y=-2200000\"\r\n" );
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document.write( "\"y=1760\"\r\n" );
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document.write( "Substituting in \r\n" );
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document.write( "\"36x+%2B+11y+=+100000\"\r\n" );
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document.write( "\"36x+%2B+11%281760%29+=+100000\"\r\n" );
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document.write( "\"36x+%2B+19360+=+100000\"\r\n" );
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document.write( "\"36x+=+80640\"\r\n" );
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document.write( "\"x=2240\"\r\n" );
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document.write( "So they should produce 2240 pounds of regular sausage and 1760 pounds of \r\n" );
document.write( "lite sausage.\r\n" );
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document.write( "Edwin
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