document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1169805>Question 1169805</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Q-4: [7+3+5+5Marks] A manufacturer has 3 machines〖 B〗_1,B_2  and B_3, make 35%, 40% and 25%, respectively, of the products. It is known from experience that 2%, 3% and 1% of the products made by each machine respectively are defective. If a finished product is randomly selected:<BR>\n" );
document.write( "A-What is the probability that it is defective?<BR>\n" );
document.write( "B-What is the probability that it is not defective?<BR>\n" );
document.write( "C-If the product is defective, what is the probability it was made by machineB_3?<BR>\n" );
document.write( "D-If the product is not defective, what is the probability that it was made by machineB_1?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #794657 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=794657\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> --------D--------ND-----Total<BR>\n" );
document.write( "B1------7--------343----350<BR>\n" );
document.write( "B2-----12--------388----400<BR>\n" );
document.write( "B3-----2.5-------247.5---250<BR>\n" );
document.write( "--------21.5------978.5--1000\r<BR>\n" );
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document.write( "probability defective is 2.15% skewed towards the left a little consistent with B1 and B2 predominating. <BR>\n" );
document.write( "-<BR>\n" );
document.write( "not defective is the complement or 97.85%<BR>\n" );
document.write( "-<BR>\n" );
document.write( "if defective, made by B3 is 2.5/21.5 or 11.63% probability<BR>\n" );
document.write( "-<BR>\n" );
document.write( "if not defective, 343/978.5 made by B1 or 35.05% </SPAN>\n" );
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