document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1169804>Question 1169804</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Q-2: [5+5+5+5 Marks4] A six person committee composed of Ali, Ahmed, Adnan, , Omer, Fahed, and Adam is to select a chairperson, secretary, and treasurer.\r<BR>\n" );
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document.write( "a)	 In how many ways can be this done?<BR>\n" );
document.write( "b)	In how many ways can be this done if either Ali or Ahmed must be chairperson?<BR>\n" );
document.write( "c)	In how many ways can be this done if Adnan must hold one of the offices?<BR>\n" );
document.write( "d)	In how many ways can be this done if both Fahed and Adam must hold office?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #794648 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=794648\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6*5*4=120 ways assuming nobody may hold more than one office.<BR>\n" );
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document.write( "2 ways for the first, then 5 for the second and 4 for the third.  40 ways<BR>\n" );
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document.write( "3*(5*4)=60 the three comes from the three possible offices he may hold<BR>\n" );
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document.write( "3 ways they can hold two offices, 4 people left to take the third office, so 12 ways. </SPAN>\n" );
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