document.write( "Question 1169800: Hi
\n" ); document.write( "John has 36 coins comprising 20c 50c and $1 coins. He has twice as many $1 coins as 20c coins and the value of the 50c coins $4.40 more than the total value of the 20c coins.\r
\n" ); document.write( "\n" ); document.write( "How many $1 coins does he have.\r
\n" ); document.write( "\n" ); document.write( "Thanks \r
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Algebra.Com's Answer #794647 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Let x be the number of 20c coins.

\n" ); document.write( "Then 2x is the number of $1 coins (twice as many as 20 cent coins).

\n" ); document.write( "Then 36-3x is the number of 50c coins (the total number of coins is 36).

\n" ); document.write( "The value of the 50c coins is $4.40 more than the value of the 20c coins:

\n" ); document.write( "\"50%2836-3x%29+=+20%28x%29%2B440\"
\n" ); document.write( "\"1800-150x+=+20x%2B440\"
\n" ); document.write( "\"1360+=+170x\"
\n" ); document.write( "\"x+=+8\"

\n" ); document.write( "ANSWER: The number of $1 coins is 2x = 16.

\n" ); document.write( "The solution can be found much more quickly informally using logical reasoning and a bit of simple arithmetic.

\n" ); document.write( "For the difference between the value of the 50c coins and the 20c coins to be $4.40, the value of the 50c coins must be a whole dollar amount and the number of 20c coins must be 3, or 8, or 13, or....

\n" ); document.write( "Now do some quick trial and error arithmetic:

\n" ); document.write( "3 20c coins (value $0.60) means 10 50c coins (value $5.00); 3 20c coins means 2*3=6 $1 coins. The total number of coins is 3+10+6 = 19. Not right....

\n" ); document.write( "8 20c coins (value $1.60) means 12 50c coins (value $6.00); 8 20c coins means 2*8=16 $1 coins. The total number of coins is 8+12+16 = 36. CORRECT!

\n" ); document.write( "ANSWER: 16 $1 coins

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