document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=16316>Question 16316</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you please help me with this problem    {9a-3d=3<BR>\n" );
document.write( "                                            {3a+8d=-17<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7946 by </B><A HREF=/tutors/aboutme.mpl?userid=shirsenduban><B>shirsenduban(10)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shirsenduban><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> from equation 2 multiply both sides by 3<BR>\n" );
document.write( "then subtract the equation that you have got from the 1 equation and u will get value of d . put the value of d in any equation and get value of a </SPAN>\n" );
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