document.write( "Question 1169773: A jar of coins contain Nickel, Dime and quarter totaling $6.75. There are three fewer quarter than nickels. They are three more dimes than the total number of nickels and quarter. Find the number of each \n" ); document.write( "
Algebra.Com's Answer #794598 by ankor@dixie-net.com(22740)\"\" \"About 
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A jar of coins contains Nickels, Dimes and quarters totaling $6.75.
\n" ); document.write( " .05n + .10d + .25q = 6.75
\n" ); document.write( "There are three fewer quarters than nickels.
\n" ); document.write( " q = n - 3
\n" ); document.write( "They are three more dimes than the total number of nickels and quarters.
\n" ); document.write( " d = n + q + 3
\n" ); document.write( "replace q with (n-3)
\n" ); document.write( " d = n + (n-3) + 3
\n" ); document.write( " d = 2n
\n" ); document.write( "We know q = (n-3) and d = 2n, replace q and d in the first equation
\n" ); document.write( ".05n + .10(2n) + .25(n-3) = 6.75
\n" ); document.write( ".05n + .20n + .25n - .75 = 6.75
\n" ); document.write( ".50n = 6.75 + .75
\n" ); document.write( ".50n = 7.50
\n" ); document.write( "n = 7.50/.5
\n" ); document.write( "n = 15 nickels
\n" ); document.write( "then
\n" ); document.write( "d = 2(15) = 30 dimes
\n" ); document.write( "and
\n" ); document.write( "q = 15 - 3 = 12 quarters
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if that works
\n" ); document.write( ".05(15) + .10(30) + .25(12) = 6.75
\n" ); document.write( " \n" ); document.write( "
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