document.write( "Question 1169773: A jar of coins contain Nickel, Dime and quarter totaling $6.75. There are three fewer quarter than nickels. They are three more dimes than the total number of nickels and quarter. Find the number of each \n" ); document.write( "
Algebra.Com's Answer #794597 by Boreal(15235)\"\" \"About 
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quarters=x
\n" ); document.write( "nickels=x+3
\n" ); document.write( "dimes=2x+6, the x+x+3+3
\n" ); document.write( ".25x+.05(x+3)+.10(2x+6)=6.75
\n" ); document.write( ".50x+.75=6.75
\n" ); document.write( "x=12 quarters 3.00
\n" ); document.write( "x+3=15 nickels 0.75
\n" ); document.write( "2x+6=30 dimes 3.00
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