document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1169484>Question 1169484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> According to a study done by students, the height for Asian adult males is normally distributed with an average of 66 inches and a standard deviation of 2.5 inches. Suppose one Asian adult male is randomly chosen. Let X = height of the individual.\r<BR>\n" );
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document.write( "I need help with the following:<BR>\n" );
document.write( "1) find the probability of an Asian male is over 71 inches tall<BR>\n" );
document.write( "2) find the middle 40% of heights fall between what two values?<BR>\n" );
document.write( "3) Write the probability statement.<BR>\n" );
document.write( " P(x1 < X < x2) =???\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #794596 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=794596\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(x-mean)/sd<BR>\n" );
document.write( "or (71-66)/2.5<BR>\n" );
document.write( "so the first is the probability z>2 which=0.0228<BR>\n" );
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document.write( "middle 40% is between the 30th and 70th percentiles.<BR>\n" );
document.write( "from the table or calculator invnorm(.30,0,1) and (.70,0,1) or between-0.5244 nd +0.5244<BR>\n" );
document.write( "-0.5244=(x-66)/2.5<BR>\n" );
document.write( "x=64.69<BR>\n" );
document.write( "and at the upper end 67.31<BR>\n" );
document.write( "(64.69, 67.31) inches\r<BR>\n" );
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document.write( "P(64.69 inches <X<67.31 inches)=0.40\r<BR>\n" );
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document.write( " </SPAN>\n" );
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