document.write( "Question 1169754: A tank containing 50 litres of water develops a leak and loses water at a constant rate. After 20 minutes it contains 40 litres. After further 30 minutes the tank is 5% of its full capacity. Determine the tank's capacity. \n" ); document.write( "
Algebra.Com's Answer #794573 by ikleyn(52781)\"\" \"About 
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document.write( "From first two sentences, we have this equation\r\n" );
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document.write( "    V(t) = 50 - a*t.\r\n" );
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document.write( "representing the current volume V(t) as a function of time, t, in minutes,\r\n" );
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document.write( "and \"a\" is the constant leaking rate in liters per minute.\r\n" );
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document.write( "At t= 20 minutes,  \r\n" );
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document.write( "    V(20) = 40 = 50 - a*20,\r\n" );
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document.write( "which gives  a = \"%2850-40%29%2F20\" = \"10%2F20\" = 0.5  liters per minute.\r\n" );
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document.write( "After further 30 minutes,  the volume of the water in the tank is\r\n" );
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document.write( "    V(50) = 40 - 0.5*30 = 40 - 15 = 25 liters.\r\n" );
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document.write( "So, 25 liters is 5% of the tank capacity.\r\n" );
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document.write( "Hence, the total capacity of the tank is  \"25%2F0.05\" = 500 liters.\r\n" );
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document.write( "ANSWER.  The total capacity of the tank is  \"25%2F0.05\" = 500 liters.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Do not accept nothing from the post by @josgarithmetic,\r
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