document.write( "Question 1169733: What is the equation in standard form of the circle whose center is at (2,8) and passes through the origin? \n" ); document.write( "
Algebra.Com's Answer #794540 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "the equation in standard form of the circle:\r
\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\"\r
\n" ); document.write( "\n" ); document.write( "given: center is at (\"2\",\"8\")=(\"h\",\"k\")\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%5E2%2B%28y-8%29%5E2=r%5E2\"\r
\n" ); document.write( "\n" ); document.write( "given: passes through the origin:(\"0\",\"0\")\r
\n" ); document.write( "\n" ); document.write( "use it to calculate radius\r
\n" ); document.write( "\n" ); document.write( "\"%280-2%29%5E2%2B%280-8%29%5E2=r%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"4%2B64=r%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"68=r%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "and your formula is: \"%28x-2%29%5E2%2B%28y-8%29%5E2=68\"\r
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