document.write( "Question 1169633: An athletic store sells about 200 pairs of basketball shoes per month when it charges $120 per pair. For each $2 increase in price, the store sells two fewer pairs of shoes. How much should the store charge to maximize monthly revenue? What is the maximum monthly revenue? \n" ); document.write( "
Algebra.Com's Answer #794531 by josgarithmetic(39617)\"\" \"About 
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document.write( "PRICE    QUANTITY SOLD      REVENUE\r\n" );
document.write( " 120          200\r\n" );
document.write( " 120+2        200-2\r\n" );
document.write( " 120+4        200-4\r\n" );
document.write( ".\r\n" );
document.write( ".\r\n" );
document.write( " 120+x        200-x        (120+x)(200-x)\r\n" );
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\n" ); document.write( "R for Revenue,
\n" ); document.write( "\"highlight_green%28R=%28120%2Bx%29%28200-x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Find the zeros of R. In the exact middle will be the x value for maximum revenue.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "120+x=0,...
\n" ); document.write( "and then
\n" ); document.write( "200-x=0,...
\n" ); document.write( "and then find the exact middle value.\r
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\n" ); document.write( "\n" ); document.write( "Maximum R when x is 40.
\n" ); document.write( "This corresponds to price \"120%2B40=160\" dollar per pair, for maximum revenue of \"160%2A%28200-40%29=180%2A160=25600\" dollars.
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