document.write( "Question 1169633: An athletic store sells about 200 pairs of basketball shoes per month when it charges $120 per pair. For each $2 increase in price, the store sells two fewer pairs of shoes. How much should the store charge to maximize monthly revenue? What is the maximum monthly revenue? \n" ); document.write( "
Algebra.Com's Answer #794531 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "PRICE QUANTITY SOLD REVENUE\r\n" ); document.write( " 120 200\r\n" ); document.write( " 120+2 200-2\r\n" ); document.write( " 120+4 200-4\r\n" ); document.write( ".\r\n" ); document.write( ".\r\n" ); document.write( " 120+x 200-x (120+x)(200-x)\r\n" ); document.write( " \n" ); document.write( "R for Revenue, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Find the zeros of R. In the exact middle will be the x value for maximum revenue.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "120+x=0,... \n" ); document.write( "and then \n" ); document.write( "200-x=0,... \n" ); document.write( "and then find the exact middle value.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Maximum R when x is 40. \n" ); document.write( "This corresponds to price |