document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1169602>Question 1169602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle having an area of 201.062 cm2\r<BR>\n" );
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document.write( "is to be divided into two segments by a chord which is 3 cm from the center\r<BR>\n" );
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document.write( "of the circle.<BR>\n" );
document.write( "a. Compute the area of the smaller segment.<BR>\n" );
document.write( "b. Determine the area of the larger segment. \r<BR>\n" );
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document.write( "3. A wheel has a diameter of 100 centimeters. The wheel is supporting a cart moving at 48 kilometers per hour. What<BR>\n" );
document.write( "is the angular velocity of the wheel in rpm? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #794487 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=794487\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of the smaller \"pie wedge\" sector, A_sector = R^2*theta/2, <BR>\n" );
document.write( "where R = the radius, theta = the wedge angle.<BR>\n" );
document.write( "Since the chord is 3 cm from the center, the half angle is given by:<BR>\n" );
document.write( "arccos(3/R) = 1.1864.  Thus the angle theta = 2.373. <BR>\n" );
document.write( "The area of the segment will be the sector area minus the triangular portion<BR>\n" );
document.write( "The area of this portion is 2(3*sqrt(R^2-3^2)/2) = 3*sqrt(55)<BR>\n" );
document.write( "The radius, R = sqrt(A/pi) = sqrt(201.062/pi) = 8<BR>\n" );
document.write( "Finally, the area of the segment is 75.9296 - 3*sqrt(55) = 53.681<BR>\n" );
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