document.write( "Question 1169546: A physical fitness association is including the mile run in its secondary-school fitness test. The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a standard deviation of 50 seconds. Find the probability that a randomly selected boy in secondary school can run the mile in less than 345 seconds.
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\n" ); document.write( ".5107
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\n" ); document.write( ".0107
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\n" ); document.write( ".9893
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\n" ); document.write( ".4893
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Algebra.Com's Answer #794433 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the probability is .0107\r
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\n" ); document.write( "\n" ); document.write( "i used the ti-84 plus calculaor.\r
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\n" ); document.write( "\n" ); document.write( "there are several online calculators you can use that will provide the same answer to you.\r
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\n" ); document.write( "\n" ); document.write( "one of the calculators that i use can be found at https://www.calculator.net/z-score-calculator.html?c1raw=-2.3&c1mean=0&c1sd=1&calctype=zscore&x=66&y=25\r
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\n" ); document.write( "\n" ); document.write( "the calculator can work off of z-scores or off of raw scores.\r
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\n" ); document.write( "\n" ); document.write( "put in a mean of 460 and a standard deviation of 50 and a raw score of 345.
\n" ); document.write( "hit calculate and your answer shows up.\r
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\n" ); document.write( "\n" ); document.write( "here's what it shows.\r
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\n" ); document.write( "\n" ); document.write( "the calculator tells you what the z-score is (-2.3)\r
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\n" ); document.write( "\n" ); document.write( "you can calculate the z-score yourself by using the formula of:
\n" ); document.write( "z-score = (x-m)/s
\n" ); document.write( "x is the raw score
\n" ); document.write( "m is the mean
\n" ); document.write( "s is the standard deviation.
\n" ); document.write( "in your problem (x-m)/s becomes (345-460)/50 = -2.3\r
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\n" ); document.write( "\n" ); document.write( "if you are using the z-score rather than the raw score, you would enter a mean of 0 and a standard deviation of 1 and give it the z-score instead of the raw score.\r
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\n" ); document.write( "\n" ); document.write( "you would get the following results.\r
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