document.write( "Question 1169617: H= -5t^2+20t models the height of a ball that is kicked into the air, where H is the ball's height in meters and t is time in seconds after being kicked.\r
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document.write( "a) How long is the ball in the air for?\r
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document.write( "b) When will the ball reach its maximum height?\r
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document.write( "c) What is the maximum height reached by the ball?\r
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document.write( "d) At what time(s) will the ball be 15 meters in the air?
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Algebra.Com's Answer #794400 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! The height of the ball as a function of the time is represented by a parabola. \n" ); document.write( "The vertex of the parabola with equation y = ax^2 + bx + c, is at x = -b/2a. \n" ); document.write( "Thus, the time to reach maximum height = -20/-10 = 2 s. The ball is in the air for \n" ); document.write( "twice that, or t = 4 s. \n" ); document.write( "The maximum height is given by H(2) = -5(2)^2 + 20(2) = -20 + 40 = 20 m \n" ); document.write( "15 = -5t^2 + 20t -> -5(t^2 - 4t + 3) = 0. This factors as (t-3)(t-1) = 0. \n" ); document.write( "Thus, there are two times when the ball is at 15 m, t = 1s and t = 3s. \n" ); document.write( " |