document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1169522>Question 1169522</A>: <I><SPAN STYLE=\"word-break: break-all;\"> C's age is 6 more than the sum of the ages of A and B. Five years from now A will be half as old as C is now. Five years ago A was 1/3 as old as B will be five years hence. Find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #794398 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=794398\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write an equation for each statement, try to get b and c in term of a<BR>\n" );
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document.write( " C's age is 6 more than the sum of the ages of A and B.<BR>\n" );
document.write( "c = a + b + 6<BR>\n" );
document.write( " Five years from now A will be half as old as C is now.<BR>\n" );
document.write( "a + 5 = .5c<BR>\n" );
document.write( "multiply both sides by 2<BR>\n" );
document.write( "2(a+5) = c<BR>\n" );
document.write( "c = 2a + 10<BR>\n" );
document.write( " Five years ago A was 1/3 as old as B will be five years hence.<BR>\n" );
document.write( "a - 5 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >(b+5)<BR>\n" );
document.write( "Get rid of the annoying fraction, multiply both sides by 3<BR>\n" );
document.write( "3(a-5) = b + 5<BR>\n" );
document.write( "3a - 15 = b + 5<BR>\n" );
document.write( "3a - 15 - 5 = b<BR>\n" );
document.write( "b = 3a - 20<BR>\n" );
document.write( "in the first equation replace c with (2a+10), replace b with (3a-20)<BR>\n" );
document.write( "2a + 10 = a + (3a - 20) + 6<BR>\n" );
document.write( "2a + 10 = 4a - 14<BR>\n" );
document.write( "10 + 14 = 4a - 2a<BR>\n" );
document.write( "24 = 2a<BR>\n" );
document.write( "a = 12 yrs<BR>\n" );
document.write( "then<BR>\n" );
document.write( "b = 3(12) - 20<BR>\n" );
document.write( "b = 16 yrs<BR>\n" );
document.write( "and<BR>\n" );
document.write( "c = 2(12) + 10<BR>\n" );
document.write( "c = 34 yrs<BR>\n" );
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document.write( "See if that checks out in the first equation<BR>\n" );
document.write( "34 = 12 + 16 + 6<BR>\n" );
document.write( "34 = 34\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
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document.write( " Find their present ages. </SPAN>\n" );
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