document.write( "Question 1169566: yato is twice as old as his brother yukine. the quotient of their ages five years ago was seven less than yukine’s present age. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #794374 by josgarithmetic(39617)\"\" \"About 
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Yato, 2b\r
\n" ); document.write( "\n" ); document.write( "Brother Yukine, b\r
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\n" ); document.write( "\n" ); document.write( "Second sentence, \"%282b-5%29%2F%28b-5%29=b-7\"\r
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\n" ); document.write( "\"b%5E2-14b%2B40=0\"
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\n" ); document.write( "\"b=%2814%2B-sqrt%2836%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"cross%28b=%2814%2B-+6%29%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "The one which works: b=4\r
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\n" ); document.write( "R E T R Y
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\n" ); document.write( "\n" ); document.write( "Returning to quadratic,
\n" ); document.write( "\"b%5E2-14b%2B40=0\"\r
\n" ); document.write( "\n" ); document.write( "Factorize,
\n" ); document.write( "\"%28b-4%29%28b-10%29=0\"\r
\n" ); document.write( "\n" ); document.write( "Possible solutions to check, b=4 or b=10.\r
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\n" ); document.write( "\n" ); document.write( "Using the quotient description \"%282b-5%29%2F%28b-5%29=b-7\"\r
\n" ); document.write( "\n" ); document.write( "b if 4
\n" ); document.write( "\"%288-5%29%2F%284-5%29=4-7\"
\n" ); document.write( "arithmetic works but either age five years ago must not be negative.\r
\n" ); document.write( "\n" ); document.write( "b if 10
\n" ); document.write( "\"%2820-5%29%2F%2810-5%29=10-7\"
\n" ); document.write( "\"15%2F5=3\"
\n" ); document.write( "\"3=3\"
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\n" ); document.write( "b=4 will not work.
\n" ); document.write( "b=10 will work.
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