document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=108873>Question 108873</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the perimeter of a right triangle if the hypotenuse is twice as long as one of the legs and the other leg is 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #79436 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=79436\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a^2+b^2=c^2<BR>\n" );
document.write( "a^2+3^2=(2a)^2<BR>\n" );
document.write( "a^2+9=4a^2<BR>\n" );
document.write( "-4a^2+a^2+9=0<BR>\n" );
document.write( "-3a^2+9=0<BR>\n" );
document.write( "3a^2-9=0 multiply each side by -1<BR>\n" );
document.write( "3(a^2-3)=0<BR>\n" );
document.write( "a^2=3<BR>\n" );
document.write( "a=sqrt(3), b=3, c=2sqrt(3)<BR>\n" );
document.write( "perimeter=sqrt(3)+3+2sqrt(3)<BR>\n" );
document.write( "= 3+3sqrt(3)<BR>\n" );
document.write( "Always check:<BR>\n" );
document.write( "(sqrt(3))^2+3^2=(2sqrt(3))^2<BR>\n" );
document.write( "3+9=4*3 true<BR>\n" );
document.write( "Ed\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );